Abinitio Interview Question 42

 

Abinitio Interview Question   42

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Abinitio Interview Question 42

Input 1 Output 1 1,2 1,2,3 1,2,3,4 1,2,3,4,5

input --> 

Normalize(length=5) 

         (normalize) out.val::in.val+index -->

 

1

2

3

4

5

 

Scan {} ->

type temporary_type=

begin

string(int) str;

decimal("") cnt;

end;

out::initialize(in)=

begin

temp.str::'';

temp.cnt::0;

end;

 

out::scan(temp,in)=

begin

temp.str::if(temp.cnt==0)'1' else string_concat(temp.str,",",temp.cnt+1); 

temp.cnt::temp.cnt+1;

end;

out::finalize(temp,in)=

begin

out.str::temp.str;

end;

->output

Output

1

1,2

1,2,3

1,2,3,4

1,2,3,4,5

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