Abinitio Interview Question 43

                                     Abinitio Interview Question 43




cust_id, card_type
111,  platinum
111,  gold
111,  silver
222,  ruby
222,  gold
222,  platinum
222,  diamond
333,  iron
333,  copper
333,  gold

Find out the customer 
who has all 3 - diamond,platinum and gold called premium customer.

constant string1  =diamond
constant string2  =platinum
constant string3  =gold


//let string(20)[3]  my_vec=[vector 'diamond','platinum','gold'];

type temporary_type=
begin
decimal("") cnt;
string(",") ctypes;
end;


out::initialize(in)=
begin
temp.cnt::0;
end;

out::rollup(temp,in)=
begin

temp.cnt::if(in.card_type member [vector 'diamond','platinum','gold']) temp.cnt+1 else temp.cnt;
temp.ctypes::string_concat(temp.ctypes,in.card_type);
end;

out::finalize(temp,in)=
begin
out.cnt::temp.cnt;
out.cust_id::in.cust_id;
out.card_types::temp.ctypes;
end;

out::output_select(out)=
begin
out::if(out.cnt==3);
end


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