Abinitio Interview Question #15 | Lowest and Highest value implementatio...


Watch my YouTube video for explanation :




Please look into the class notes here for your references:

SELECT deptno,
       ename,
       sal,
       MIN(sal) KEEP (DENSE_RANK FIRST ORDER BY sal) OVER (PARTITION BY deptno) "Lowest",
       MAX(sal) KEEP (DENSE_RANK LAST ORDER BY sal) OVER (PARTITION BY deptno) "Highest"
FROM   emp
ORDER BY deptno, sal;

    DEPTNO ENAME             SAL     Lowest    Highest
---------- ---------- ---------- ---------- ----------
        10 MILLER           1300       1300       5000
        10 CLARK            2450       1300       5000
        10 KING             5000       1300       5000
        20 SMITH             800        800       3000
        20 ADAMS            1100        800       3000
        20 JONES            2975        800       3000
        20 SCOTT            3000        800       3000
        20 FORD             3000        800       3000
        30 JAMES             950        950       2850
        30 WARD             1250        950       2850
        30 MARTIN           1250        950       2850
        30 TURNER           1500        950       2850
        30 ALLEN            1600        950       2850
        30 BLAKE            2850        950       2850
Achive the above in abinitio

a. Use SCAN with ROLLUP

b.  
Replicate  ------------------->
 Input -> Sort-->                           -> JOIN (on Key DeptID)  --> O/P
Replicate-->ROLLUp(key dept) -> 




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